Search and replace all occurances of a string in all tables in a database.
From http://vyaskn.tripod.com/
--To replace all occurences of 'America' with 'USA':
EXEC SearchAndReplace 'America', 'USA'
GO
REATE PROC SearchAndReplace
(
@SearchStr nvarchar(100),
@ReplaceStr nvarchar(100)
)
AS
BEGIN
-- Copyright © 2002 Narayana Vyas Kondreddi. All rights reserved.
-- Purpose: To search all columns of all tables for a given search string and replace it with another string
-- Written by: Narayana Vyas Kondreddi
-- Site: http://vyaskn.tripod.com
-- Tested on: SQL Server 7.0 and SQL Server 2000
-- Date modified: 2nd November 2002 13:50 GMT
SET NOCOUNT ON
DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110), @SQL nvarchar(4000), @RCTR int
SET @TableName = ''
SET @SearchStr2 = QUOTENAME('%' + @SearchStr + '%','''')
SET @RCTR = 0
WHILE @TableName IS NOT NULL
BEGIN
SET @ColumnName = ''
SET @TableName =
(
SELECT MIN(QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME))
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_TYPE = 'BASE TABLE'
AND QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME) > @TableName
AND OBJECTPROPERTY(
OBJECT_ID(
QUOTENAME(TABLE_SCHEMA) + '.' + QUOTENAME(TABLE_NAME)
), 'IsMSShipped'
) = 0
)
WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)
BEGIN
SET @ColumnName =
(
SELECT MIN(QUOTENAME(COLUMN_NAME))
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = PARSENAME(@TableName, 2)
AND TABLE_NAME = PARSENAME(@TableName, 1)
AND DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar')
AND QUOTENAME(COLUMN_NAME) > @ColumnName
)
IF @ColumnName IS NOT NULL
BEGIN
SET @SQL= 'UPDATE ' + @TableName +
' SET ' + @ColumnName
+ ' = REPLACE(' + @ColumnName + ', '
+ QUOTENAME(@SearchStr, '''') + ', ' + QUOTENAME(@ReplaceStr, '''') +
') WHERE ' + @ColumnName + ' LIKE ' + @SearchStr2
EXEC (@SQL)
SET @RCTR = @RCTR + @@ROWCOUNT
END
END
END
SELECT 'Replaced ' + CAST(@RCTR AS varchar) + ' occurence(s)' AS 'Outcome'
END